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by
Lewis L. Spence
I do have a great interest in exploring the mathematics of acoustics and the acoustical effects on architectural designs. This knowledge will allow students to practice mathematical solutions to acoustical problems. Hopefully this exposure might instill a keener awareness of sound quality in the general environment.
I am an eighth grade mathematics teacher at the Betsy Ross Arts Magnet Middle School in the city of New Haven, Connecticut. The school has a diverse ethnic population of AfricanAmericans, Asians, AfroCaribbeans, Caucasians, and Hispanics. The AfroAmerican population accounts for about sixty percent of the total population. The curriculum allows students to complete their studies in the basic academic subject areas and still retain a strong focus on the visual and performing arts.
There is this constant complaint among our student population that mathematics is boring. One of the suggested solutions to this problem is the integration more of relevance in the presentation of the subject matter. An approach that investigates the acoustical effects on architecture and the environment might somehow provide that missing relevance. The proposed units of development will be geared for the students in the prealgebra and algebra groups since the science requires some form of algebraic manipulations. The primary objectives are:
 1) To provide practice in the basic skills of algebraic manipulations
 2) To provide practice in the application of basic mathematics in science
 3) To offer an interdisciplinary approach to mathematics
 4) To determine the nature of good acoustics
 5) To develop proposals for providing good acoustics
The phenomenon of wave propagation should require some form of visual presentation. Maybe the use of a rope, a delicate coil spring, a large container of water, could serve to demonstrate types of waves and the nature of their behavior.
The introduction of formulas to determine the speed, wavelength, frequency and intensity of a sound should provide practice in evaluating an equation. Also the students should be allowed to discover the effects of manipulating the formulas to get a required value. For example, in the formula of frequency, wavelength, and speed, what happens if a particular value is increased or decreased? The same manipulation should be applied in the formula dealing with sound intensity. From this students should get a clearer understanding of the variables which control basic acoustics.
The nature of materials and their effects on sound propagation requires some attention. Careful attention should be paid to shapes and designs with regard to how they affect sound. What constitutes noise? What constitutes good acoustics? What noise is noise? What are the basic parameters that affect good acoustics? This knowledge base should allow the students to make reasonable proposals as to what measures to take in order to provide a suitable acoustical environment.
Light waves and radio waves travel at a speed of 3 x 10 meters (186,000 miles) per second, while sound waves travel at 344 meters (1100 ft) per second at 70 F. Unlike the other mentioned waves, sound waves do not travel in a vacuum; they require a material medium in the form of a solid, liquid or gas. In water sound will travel at a speed of about 1500 meters per second (5000 ft/sec), which is about five times its speed in air. While in a steel material the speed could be more than three times faster than in water.
The frequency, f, is the number of vibrations or oscillation per second occurring in the material. The unit of measurement is Hertz (Hz). One thousand Hertz is called one kilohertz (kHz)
Period, ( (Greek, tau) is the measure of the time for one oscillation. Since the frequency tells how many oscillations occur in one second, and the period tells the time for one oscillation, one could find the value of the other if the value of one of the features is known. For example: if the frequency is 200Hz, that is 200 oscillations in one second, then the period, the time for one oscillation would be 1/200 = 0.02 seconds. Likewise, if the period, (, is 0.01second, the frequency would be 1/0.01 = 100 Hertz.
We could determine the speed or the velocity of the wave. Since speed is the distance divided by the time, which can be classified as rate. In this instance, the rate is the velocity of the sound, c = ( /(, where ( (lambda) is the wavelength. However, since 1/( = f, the velocity can be expressed as c = (f.
The velocity of sound in air is constant, 1100 ft/sec. Therefore it makes it fairly easy to determine the wavelength of a sound wave if the frequency is known. Since the velocity (1100 ft/sec) is constant which is the product of the wavelength and the frequency, it argues that if the value of the frequency is large, the value of the wavelength must be small. If the value of one is double the value of the other is halved. For example, if the frequency is1100 Hz, then the wavelength would be 1 ft. If the wavelength is doubled, 2200 Hz, then the wavelength is 0.5 ft. It will be the same effect on the frequency if the wavelength were doubled or halved.
The ear is the organ in humans which perceives sound. Reasonable acoustics is somewhat subjective; it depends on individual and cultural norms and standards which are not necessarily permanent but acceptable for the age, time and setting. Sound is actually the result of “an organized disturbance of pressure in the air. The human ear is capable of perceiving sounds which are so weak that they cause the ear drum to displace by less than the size of a hydrogen atom which has a diameter of about a billionth of an inch. Such a faint sound has a pressure disturbance of about a billionth of one atmospheric pressure (which is about 14.7 pounds per square inch or 0.1 MPa). Extremely loud sounds which normally produce pain, have sound pressures of about one thousandth of an atmosphere.
The sound we hear is largely dependent on the frequency. It is this particular feature which determines the pitch or timber. Humans perceive sounds with tones as low as 20 Hz and high pitched as 20,000Hz. This implies that the human ear perceives sounds below the lowest tone on the piano scale which has a tone of 27.5 Hz (the note is A ), and above the highest tone which has a fundamental frequency of 4156 Hz, (the note is C).
The human ear is most sensitive to frequencies within the range of 2 and 4 kHz, which to some extent is the result of the ear canal which resonates within this frequency range. We perceive speech mainly in the frequency range of 500Hz to 3000 Hz. A man's voice which is generally lower than a female’s voice because of the lower frequency band due to the size of the vocal tract, is still perceived over the telephone even though most of the low frequencies are filtered out. The recognition is still possible because “our perception mechanism tends to fill them back in”.
Source Level (in dBA)
Faintest audible sound 0
Whisper 20
Quiet residence 30
Soft stereo in residence 40
Cafeteria 80
Cafeteria kitchen 90
Loud crowd noise 100
Accelerating motorcycle 110
Hard rock band 120
Jet engine (75 feet away) 140
1. The sound should be loud enough everywhere. The room should not absorb most of the sound waves.
2. The sound should be adequately distributed around the room. This enhancement could be achieved by having the appropriate reflecting surfaces placed at the proper angles.
3. There should enough clarity. This can be achieved by ensuring that the room does not experience excessive reverberation. The proper reflecting surfaces should provide the solution. Especially for speech, the reverberating sound waves should have only a set acceptable life span.
4. The room should be free of echoes. If a strong the reflected sound reaches the listener 1/10 of a second or greater after the listener receives the direct sound, that could distort the sound which could result in a speech which is unintelligible. The sound could also be perceived as an echo.
5. The room should be free of extra noise traffic, playground, air conditioning units, etc.
Students are expected to draw from their own experience in describing sound and how it affects their lives and the lives of others.
Describe your world without sound for a week.
How would it affect the people around us?
How do we communicate without sound?
How do we produce sound?
How do we measure the intensity or perceived loudness of a sound?
Activity: Students can explore differences in sound by banging on different objects.
They could experiment on a set of the same type of objects varying in size or length. They should be allowed to make some inferences from the results. From this demonstration the word “pitch” could be introduced.
The use of a sound meter will allow students to produce different sounds at different volumes. They can use a sound meter to measure the loudness from varying distances.
They can be assigned the task of designing a room or a box of a given dimension using plywood for the outer walls. Their primary task should be to use an insulating material on the inside to insulate the sound from getting to the out side environment. To test the effectiveness, a sound source (an alarm clock) is set off inside the closed room or box and the emitting sound is measured from a set distance using a sound meter. This process can be repeated using different insulating materials.
Mind teaser: Which famous musician in his adult life was deaf yet was able to write classical music? How was he able to accomplish such a task?
Students should be familiar with the method by which sound waves are propagated. The feature of a longitudinal wave can be helpful in demonstrating amplitude, crest and trough of the wave. In addition, a slinky could be helpful in showing how the wave travels through the material. Students need to note the forward and backward movement of the coils as the disturbance or vibration moves from one point to the other with each section returning to its original position. This forward and backward movement represents one cycle. A repetition of this movement represents another cycle. The definition of frequency, f, could then be introduced as the number of times the wave goes through a cycle in one second (frequency, f, is the number of cycles completed in one second), measured in the unit of Hertz, Hz (1000 Hz = 1 kilohertz). What is one megahertz?
The time taken for the completion of one cycle is the period, (, in seconds. The distance on a wave from one crest to the next is called the wavelength, or the distance from one trough to the next (the wavelength determines the frequency of the wave).
The speed or velocity of a moving object is the distance traveled divided by the time it takes the object to move that distance. This is also referred to as rate (where velocity, v, is equal to the distance, d, divided by the time, (: c = d/().
In the case of a wave, the velocity, c, is equal to the wavelength, (, divided by the period, t (c = (/().
Examples: What is the velocity of a wave that has a wavelength of 10m and a period of 2 seconds?
Solution: c = (/(
c = 10/2 = 5 m/sec
If a wave has a period, (, of 0.01sec, what is the frequency, f ( frequency tells the number of cycles per second. We are given the information that in 0.01 seconds there was only one cycle). The task is to find how many cycles there are in one second.
Solution: f = 1/( and ( = 1/f
In the equation where c = (/(, it can also be expressed as c = ( f.
Since the speed of sound in air is a constant, 1100 feet per second, we can apply the formula to determine the wavelength if the frequency or the wavelength is known. Activity: What is my note?
Each student can measure his/her height in feet. This measurement should be used in the formula (c = (() to calculate the frequency. A chart with the frequency of the notes on the piano scale would be useful in assisting the student in identifying the particular key. The student should strike the key to acquaint himself/herself with that tone.
When someone speaks in a room, the speech is intelligible if there is an appropriate time delay for the reflected sound. This delay is the difference between the time it takes for the direct sound and the reverberating sound to get to the listener. A time delay longer than 0.075 seconds (75 milliseconds) produces echoes which distort the listening process.
Activity:
 Jennifer sits 30 feet from the speaker in an auditorium which is140 feet long. What is the delay time, T?
 Solution: Distance from Jennifer to the back of the room is 14030 = 110 ft.
 Total distance of the path of the reflected sound from the speaker to the back of the room reflected to Jennifer: 140 + 110 = 250 ft.
 Distance of the path of the direct sound from the speaker to Jennifer = 30ft.
 Difference in path of the distance of the reflected sound and the direct sound: 140 + 110 ñ 30 = 220ft.
What is the delay time, T? (The time taken to travel 220 ft.)
 (220 ft.is the extra distance the reflected sound had to travel compared to the direct sound)
Sound travels 1100 feet per second. Therefore the time for 220feet is, T = 220/1100 = 0.2 seconds
Would this be an acceptable time delay?
If this time delay is unacceptable, what can be done to improve the situation?
Project: Students cold use cardboard material to design the four walls of the room. A single piece of polystyrene (that white packing material) can be used for the floor. Toothpicks with cutouts can be used to show the location of the speaker and the listener. Using a scale of one inch being equivalent to ten feet, the students can show varying adjustments from which they can calculate several time delays. To show the path of the sound wave, the students could use pieces of thread of different colors to indicate the direct wave to the listener and the reflected wave from the back of the room leading to the listener.
Evaluation:
What is time delay?
What is an acceptable time delay?
How does excessive time delay affect sound quality?
How is time delay calculated?
Since light travels faster than sound we can use this situation to measure the distance of a sound. Whenever there is a thunderstorm (if we are within a reasonable distance) we might be able to see the lightening then afterward we hear the thunder light travels faster than sound. The same is true for a fireworks display in the distance. If we could measure the time the flash is seem, then measure the time it takes for us to hear the sound, we could use this information to determine how far away the fireworks is. The same is true for the thunderstorm ñ we could tell how far away the storm is located
Activity:
Fireworks: After the flash we hear the sound 2 seconds later. How far away is it?
Since we know that sound travels at 1100 ft per seconds, therefore the distance the sound travels in 2 seconds is, 2 x 1100 = 2200ft
If a person is standing 6600ft away, how long should it take for him or her to hear the same sound? 66600/1100 = 6 seconds.
Students can be asked to find the solutions for similar problems, varying the time and distance. They could be asked to design an activity that could demonstrate the speed of sound in air.
Suggested Readings 
Architectural Acoustics: Principles and Practice; William J. Cavanaugh
Noise Control Manualfor Residential Buildings; David A. Harris
Student Reading List 
Noise Control; A Primer; Alberto Behar
Noise Pollution: Earth’s Conditions Series; Zachary Inseth
Rossing, D. Thomas, The Science of Sound ñ Second Edition, AddisonWesley Publishing Company, USA, 1990
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